Thread: Finite Theory of the Universe, Dark Matter Disproof and Faster-Than-Light Speed

I wrote a theory that explains black holes, disproves dark energy, disproves dark matter, explains the galactic rotation curve, works well with the perihelion precession disparity and the gravitational light bending.

A presentation can be found here:
https://www.fuzemeeting.com/replay_meeting/fccff073/2191153
And its website can be found here:
http://fornux.com/ft/


Regards,
-Phil

Originally Posted by philippeb8

I wrote a theory that explains black holes, disproves dark energy, disproves dark matter, explains the galactic rotation curve, works well with the perihelion precession disparity and the gravitational light bending.

A presentation can be found here:
https://www.fuzemeeting.com/replay_m...cff073/2191153
And its website can be found here:
http://fornux.com/ft/


Regards,
-Phil

A very interesting presentation. That being said, there is one item that I can't quite get my head around. On the slide regarding the F. T. Reference Frame, the one marked 'Absolute', I don't quite understand the 'infinte' beam of light. Can you clarify, please? And have you clarified anything esle in the presentation as a result of the various comments?

Originally Posted by David E. Eaton Sr.

A very interesting presentation. That being said, there is one item that I can't quite get my head around. On the slide regarding the F. T. Reference Frame, the one marked 'Absolute', I don't quite understand the 'infinte' beam of light. Can you clarify, please? And have you clarified anything esle in the presentation as a result of the various comments?

As seen from the driver of the spaceship, a beam of light emitted in the opposing direction will be seen to travel at infinite speed. This is because the absolute reference frame is defined by the strongest gravitational potential (Earth). The beam of light going to the right as seen by an observer on the surface of the Earth will be seen to travel at speed c but not for the driver. This is because the driver's clock tick is infinitely slow and thus its perception of the speed of the light beam is infinitely fast.

Furthermore those are the corrections to my presentation:
1) The galactic rotation curve is given by:
v = sqrt(Gm/x) / ((m/x+h) / (m/r+h))

Where:
h is the gravitational potential of the Universe at that scale
r is the distance of the Sun from the center of the Milky Way (not the radius of the galaxy)

2) The reference frame of an object in the middle of the solar system is relative to the center of the Milky Way (not the Sun).

3) Jumping into a black hole is not safe as black holes cannot exist and thus you will crash into a very massive black star. Do not try this at home.

Originally Posted by philippeb8

As seen from the driver of the spaceship, a beam of light emitted in the opposing direction will be seen to travel at infinite speed. This is because the absolute reference frame is defined by the strongest gravitational potential (Earth). The beam of light going to the right as seen by an observer on the surface of the Earth will be seen to travel at speed c but not for the driver. This is because the driver's clock tick is infinitely slow and thus its perception of the speed of the light beam is infinitely fast.

Ah...that's what I missed..."as seen from the driver..." -- thanks.

Originally Posted by philippeb8

Furthermore those are the corrections to my presentation:
1) The galactic rotation curve is given by:
v = sqrt(Gm/x) / ((m/x+h) / (m/r+h))

Where:
h is the gravitational potential of the Universe at that scale
r is the distance of the Sun from the center of the Milky Way (not the radius of the galaxy)

2) The reference frame of an object in the middle of the solar system is relative to the center of the Milky Way (not the Sun).

3) Jumping into a black hole is not safe as black holes cannot exist and thus you will crash into a very massive black star. Do not try this at home.

LOL...I won't....I remember that part of the discussion....thank you for the clarifications....