Interestingly, it's not all that difficult to calculate the effect of atmospheric pressure on tides. On a standard day, 1 ATM = 101.3 kPa = 14.7 lb per sq in = 1,013.2501 millibars = 29.9212583 inches of mercury (Hg). Also equivalent to 1 ATM is 30 feet of seawater.
At second landfall, near Buras-Triumph, Louisiana, Katrina's minimum pressure measured 27.17 in Hg. That's 90.81% of standard day, which means it's also 9.19% below std day. To compute the effect on mean sea level, one merely need multiple 30 feet by 9.19%, which yields 2.76 feet.
Needless to day, the drop in pressure only accounts for about 13% of the roughly 20 foot storm surge that hit the levees and Slidell, the first town north of New Orleans. Slidell's main street is 16 feet above mean sea level, yet it was 5 feet underwater, for a total surge of 21 feet above mean sea level.
What accounted for the remaining 18 feet aka 87% i.e. 18 ft of storm surge? Primarily, two things: Large waves rapidly washing inland, while flowing back to sea slowly due to the very nearly flat land, and the strong northerly surface currents generated by sustained 125 kt winds. Combined with the nearly flat land and heavy rainfall, the storm flooded its way inland for many miles.



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