So that a + b = c?

That is, 1 = 1? some counter-proof... Sheesh!

so that a = .5 and b = .5 means that a + b = 1 (note, please, that a and b are not integers...)

Now calculate for a = 1, b = 1...

and then, maybe try a = m*1, b = n*1 ... in Euler's formulae ...

again, the point is that for a and b independent variables (a,b)

for (n = 2), vanishes in the case of Pythagorean triples, where is the interaction vector .

If a and b are dependent, the a = mb so c = mb +mb , so .

Where did a go?

If they are independent, then so , and the interaction term does not vanish.

, where is the positive unit vector for both cw and ccw Lorentz rotations in the positive quadrant of the relativistic unit circle (+1,+1) as well as the negative quadrant (-1,-1).

That is,

Furthermore, for the interaction profuct ( <1; if , then = 0, and vice versa)

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