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Thread: Fermat's last, and mine too.

  1. #11
    Moderator Neverfly's Avatar
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    Default Re: Fermat's last, and mine too.

    Welcome to the discussion board. Once a posters post count passes a certain limit, the software allows links to be posted. That is set in place to reduce Spam.
    I took the liberty of adding the link to your post for clarity.
    --Inter Arma Enim Silent Leges--
    “Science needs the light of free expression to flourish. It depends on the fearless questioning of authority, and the open exchange of ideas.” ― Neil deGrasse Tyson

    "When photons interact with electrons, they are interacting with the charge around a "bare" mass, and thus the interaction is electromagnetic, hence light. This light slows the photon down." - BuleriaChk

  2. #12
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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by uhhh View Post
    Let c=2 and a=b=1.

    If you read the Wiki page you cited (under "Theorem statement"), it says , not for any c.

    Added Link for user:
    Cited Wikipedia Page
    Suppose c is an integer.... (sigh)... but that a, b, and c are actually vectors in two dimensions (e.g., a Pythaorean triangle for a perpendicular to b), and that a,b, and c are coefficients of the vectors.....
    _______________________________________
    "Flamenco Chuck" Keyser
    The Relativistic Unit Circle Updates 03/02/2017 12:07 PM PST
    Proof of Fermat's Last Theorem Updates 03/19/2017 8:23 PM PST
    Ignore List -The Peanut Gallery.

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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by Neverfly View Post
    Welcome to the discussion board. Once a posters post count passes a certain limit, the software allows links to be posted. That is set in place to reduce Spam.
    I took the liberty of adding the link to your post for clarity.
    Thank you!

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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by BuleriaChk View Post
    Suppose c is an integer.... (sigh)... but that a, b, and c are actually vectors in two dimensions (e.g., a Pythaorean triangle for a perpendicular to b), and that a,b, and c are coefficients of the vectors.....
    Take a and b out of that sentence and read it again. You are saying that:

    "Suppose c is an integer...but that c [is] actually [a] vector in two dimensions...and c [is a] coefficient of the vector"

    Which is it?

  5. #15
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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by uhhh View Post
    Take a and b out of that sentence and read it again. You are saying that:

    "Suppose c is an integer...but that c [is] actually [a] vector in two dimensions...and c [is a] coefficient of the vector"

    Which is it?
    Look up "proof by contradiction" in mathematical logic (Google Wiki)

    Then look up dot product and cross product and independent variables. Then read my pdf.

    Then get back to me.....
    _______________________________________
    "Flamenco Chuck" Keyser
    The Relativistic Unit Circle Updates 03/02/2017 12:07 PM PST
    Proof of Fermat's Last Theorem Updates 03/19/2017 8:23 PM PST
    Ignore List -The Peanut Gallery.

  6. #16
    Moderator grapes's Avatar
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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by BuleriaChk View Post


    It only reduces to c = a+b if a=0 or b= 0, in which case c = b or c=a, respectively.
    No, implies c=a+b, and vice versa.

  7. #17
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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by BuleriaChk View Post
    Look up "proof by contradiction" in mathematical logic (Google Wiki)

    Then look up dot product and cross product and independent variables. Then read my pdf.

    Then get back to me.....
    Look up the word "non-sense", reductio ad absurdum means you assume someone and then show it leads to a contradiction.

    Not that you
    1: Assume something for a theorem that goes in opposition to what the theorem requires to be applicable. I cannot use pythagorean theorem while assuming that none of the angles in the fucking triangle is 90 degrees.
    2: Mix a bunch of concepts in the hopes it'll confuse people because most here, unlike you, know the differens between things. Many things, such as integers, are expressable in many ways. However a vector, is not one of them. Because it requires that for an integer n that pi*n is an integer which is ludacris.

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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by BuleriaChk View Post
    Look up "proof by contradiction" in mathematical logic (Google Wiki)

    Then look up dot product and cross product and independent variables. Then read my pdf.

    Then get back to me.....
    You didn't answer my question. Is c an integer or a 2-d vector?

    Note: it cannot be both.

  9. #19
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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by uhhh View Post
    You didn't answer my question. Is c an integer or a 2-d vector?

    Note: it cannot be both.
    I'm only going to answer this once in my threads.

    The connection between integer counting and the Binomial Theorem is through relativistic spin (Special Theory of Relativity).

    Pure mathematics involves imaginary widgets. It requires energy and momentum to actually create a widget. Newton and Maxwell did not address this. Einstein (and Pauli/Dirac) did address the issue.

    If you haven't geen on the journey I have to understand the Lorentz Transform, the Pauli/Dirac formulation, and relativistic spin (QFT, there is no point in going further; I am beginning to see a way to draw a diagram for this, and I will shortly be presenting my case at UCSB. Until then, if you haven't understood the Relativistic Unit Circle and the links to the Pauli/Dirac matrices, there is no point in carrying the discussion further.
    _______________________________________
    "Flamenco Chuck" Keyser
    The Relativistic Unit Circle Updates 03/02/2017 12:07 PM PST
    Proof of Fermat's Last Theorem Updates 03/19/2017 8:23 PM PST
    Ignore List -The Peanut Gallery.

  10. #20
    Moderator Neverfly's Avatar
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    Default Re: Fermat's last, and mine too.

    Quote Originally Posted by BuleriaChk View Post
    It requires energy and momentum to actually create a widget.
    Define: "Widget."

    Quote Originally Posted by BuleriaChk View Post
    If you haven't (b)een on the journey I have to understand the Lorentz Transform
    ...Like that you think you can apply the Time Dilation equation to a Photon?
    --Inter Arma Enim Silent Leges--
    “Science needs the light of free expression to flourish. It depends on the fearless questioning of authority, and the open exchange of ideas.” ― Neil deGrasse Tyson

    "When photons interact with electrons, they are interacting with the charge around a "bare" mass, and thus the interaction is electromagnetic, hence light. This light slows the photon down." - BuleriaChk

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