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- 03-26-2017, 09:24 AMHappy birthday, Tom! Sorry I missed it. I was busy this last week, then I caught a cold, and one thing and another, but anyway hope you had a good...1 replies | 20 view(s)
- 03-19-2017, 06:55 PMSo, your pdf repeats the same thing in the space of three lines, I leave off one of the repetitions and you complain I took the whole thing out of...206 replies | 3233 view(s)
- 03-19-2017, 03:46 PMNo, it was there: Again, I was just pointing out places where you claimed two expressions were equal, but it's easily shown that they're not...206 replies | 3233 view(s)
- 03-19-2017, 01:26 PMI'm just complaining about the equals signs. Your *equations* are wrong. Of course it invalidates your "proof". For *any* solution to c^n =...206 replies | 3233 view(s)
- 03-19-2017, 12:26 PMThe pdf at that link in your signature still contains your erroneous "proofs". On the first page it says: No, for positive numbers, 2ab is never...206 replies | 3233 view(s)
- 03-19-2017, 11:27 AMThe dot product (\vec{a}\cdot\vec{b}) is *always* zero, no matter which positives integers a and b are, whether they are a part of a Pythagorean...206 replies | 3233 view(s)
- 03-19-2017, 10:27 AMI was just pointing out one of the mistakes that invalidate your "proof" of Fermat's Last Theorem.206 replies | 3233 view(s)
- 03-19-2017, 05:49 AMThis is how you defined these vectors, a and b are positive integers. The dot product (\vec{a}\cdot\vec{b}) will always be zero. That means...206 replies | 3233 view(s)
- 03-18-2017, 10:20 PMLook how you defined these vectors! See above No, their dot product is always zero.206 replies | 3233 view(s)
- 03-18-2017, 03:39 PMAnd yet, you say in your post, that it is *not equal* to zero206 replies | 3233 view(s)
- 03-18-2017, 11:19 AMThe vectors a and b are perpendicular to each other, so of course their dot product is *equal* to zero. But even that doesn't mean that 2ab equals...206 replies | 3233 view(s)
- 03-14-2017, 07:32 PMSo far as we know, it is not true. As you know, it's been investigated, and it doesn't seem to fit the data. So far, anyway.24 replies | 253 view(s)
- 03-14-2017, 07:28 PMIt's still on the first page of your PDF. It's the biggest mistake you make. You cannot just set c equal to a+b, and then say QED206 replies | 3233 view(s)
- 03-14-2017, 03:24 PMGo back to your post that I asked about--that doesn't even appear in your post. Those have nothing to do with your last post either. You...206 replies | 3233 view(s)
- 03-14-2017, 01:34 PMNo, you were right, you were wrong. Binomial expansion applies to numbers not vectors. You can extend the definition, but you haven't done that....206 replies | 3233 view(s)
- 03-14-2017, 04:49 AMn=2 is definitely relevant to your "proof" because rem(a,b,n) = 0 IFF a=0 or b=0 for n=2, also. For n=2, your rem(a,b,n) equals 2ab, which can only...206 replies | 3233 view(s)
- 03-13-2017, 02:15 PMThat doesn't make sense. Example: a=2, b=3, then {\psi _{ab}} = \sqrt {{{(a + b)}^2}} = \sqrt {{a^2} + {b^2} + 2ab} = 5 . Surely we all agree...206 replies | 3233 view(s)
- 03-13-2017, 09:09 AMHe was the guy before Deshorse206 replies | 3233 view(s)
- 03-12-2017, 06:28 PMTherefore, the binomial expansion has no relevance for the proof of Fermat's Last Theorem, you're throwing in extra terms that aren't there. We...206 replies | 3233 view(s)
- 03-11-2017, 08:46 AMApparently, the smallest counter-example was found in 1988, the only example where the values are less than a million: 95800^4 + 217519^4 +...3 replies | 100 view(s)
- 03-10-2017, 06:25 PM2682440^4 + 15365639^4 + 18796760^4 = 20615673^4 You could do that by hand, in a few minutes. Both sides are equal to...3 replies | 100 view(s)
- 03-10-2017, 06:15 PMOK, fine by me, you weren't participating in the conversation anyway. Thread closed. ETA: Thread re-opened, after PM206 replies | 3233 view(s)
- 03-10-2017, 05:36 PMFermat's Last Theorem. The binomial theorem has nothing to do with the proof of Fermat's Last Theorem. Still haven't got out your calculator? :)206 replies | 3233 view(s)
- 03-10-2017, 04:33 PMI was responding to your post. If you can't do the math, get a calculator.206 replies | 3233 view(s)
- 03-10-2017, 04:00 PM123 = 93 + 103 - 1 That didn't even take a high school education.206 replies | 3233 view(s)
- 03-10-2017, 01:58 PMrem can be negative c^n = a^n + b^n + rem206 replies | 3233 view(s)
- 03-09-2017, 08:39 PMNonsense, you know that's not true, not one of those is true You're just being foolish, over-reacting so much that you cannot even see your own...206 replies | 3233 view(s)
- 03-09-2017, 07:41 PMPerfect! You mimic real words, but you have no idea what they mean, because you're blind even to your own posts.206 replies | 3233 view(s)
- 03-09-2017, 06:58 PMYou're just being foolish. Go, read your post again.206 replies | 3233 view(s)
- 03-09-2017, 06:27 PMI was trying to understand your point, that's why I posted. Maybe you should re-read your own post again, and then my post, and see if you see the...206 replies | 3233 view(s)

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