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- 03-01-2017, 10:05 PMOkay, what do you mean both sides of the equality? a^n+b^n is the only option for what can equal c^n. You cannot pick the binomial expansion,...284 replies | 2806 view(s)
- 03-01-2017, 08:38 PMBut a and b are integers, so (a+b) is an integer! It can be both a binomial and an integer (btw, I understand there's a formal mathematical...284 replies | 2806 view(s)
- 03-01-2017, 08:00 PMThere is nothing wrong with that, that's the whole point. c^n=(a+b)^n, so you only proved it for c=a+b! That's what we've been saying the whole time!...284 replies | 2806 view(s)
- 03-01-2017, 07:11 PMBut c is equal to a+b. You set it that way yourself in your "proof" Let me ask you another question. Let's assume, simply for the sake of argument...284 replies | 2806 view(s)
- 03-01-2017, 06:59 PMFirst of all, Buleria, I could link this whole conversation to reddit and they'd have the same counterarguments we have. And, if c is an integer,...284 replies | 2806 view(s)
- 03-01-2017, 06:09 PMQuoted directly from wikipidia: It states that a and b are integers. an integer plus another integer is another integer. Period. That's it. If (a+b)...284 replies | 2806 view(s)
- 03-01-2017, 04:26 PMListen. a and b are integers. Fermat's last theorem says that. (a+b) is therefore an integer. (a+b)^2 is therefore an integer. Therefore, the first...284 replies | 2806 view(s)
- 03-01-2017, 04:04 PMstop. What algebra error is made by saying that? Don't avoid the question.284 replies | 2806 view(s)
- 03-01-2017, 03:52 PMBuleria, you still haven't explained how the first step of your proof c^n=(a+b)^n is not equivalent to c=a+b. Don't give any of that "it's a...284 replies | 2806 view(s)
- 02-28-2017, 10:10 PMHere's one that's not a Pythagorean triple. 3^2+4^2\neq 7^2 However, 3^2+4^2+2*3*4= 7^2 I can give more if you want. As long as z=a+b, then...284 replies | 2806 view(s)
- 02-28-2017, 09:55 PMBut up above an example of an integer solution was given by grapes: a=3, b=4, z=7. And, yes, you can find a real number z such that z^2=(a+b)^2,...284 replies | 2806 view(s)
- 02-28-2017, 09:10 PMWow. Nice question evasion. Still waiting on that response. Also, no description of why I'm an idiot? Damn. Was really looking forward to that. ...284 replies | 2806 view(s)
- 02-28-2017, 08:37 PMBut you do need to address the c=a+b, because that's the main problem with your proof. AND YOU STILL HAVEN'T EXPLAINED WHY YOUR PROOF FAILS AT n=2!...284 replies | 2806 view(s)
- 02-28-2017, 07:26 PMAh, true. He really needs to learn that ad hominem attacks are terrible argument strategies. Note that he still hasn't answered me question about...284 replies | 2806 view(s)
- 02-28-2017, 03:37 PMI just want to point out that you STILL haven't explained how your proof fails to hold for n=2. If your proof does hold for n=2, then the pythagorean...284 replies | 2806 view(s)
- 02-27-2017, 05:14 PMOkay, both the Pythagorean theorem and the binomial expansion are true. That is a fact. If you reduce your proof to what it really says (that for any...284 replies | 2806 view(s)
- 02-27-2017, 04:58 PMRegardless of your intention, your proof, if correct, implies the pythagorean theorem is false, because your proof is still valid for n=2....284 replies | 2806 view(s)
- 02-27-2017, 04:05 PMI'm not asking about the pythagorean theorem, I'm asking about your proof. How does your proof fail to hold for n=2? Because it has to, or it's a...284 replies | 2806 view(s)
- 02-27-2017, 03:55 PMbut explain how your proof fails to hold for n=2. if you can't do that, then either the pythagorean theorem is wrong, or you are. What is stopping...284 replies | 2806 view(s)
- 02-27-2017, 03:34 PMOkay, first of all, if you start with c=a+b, and do your proof, you only prove fermat's last theorem for the case where c=a+b. That's it. You aren't...284 replies | 2806 view(s)
- 02-27-2017, 12:03 PMOr he might just be done arguing with you.284 replies | 2806 view(s)
- 02-27-2017, 12:03 PMDude, you're overcomplicating it. It's an algebra error. It has nothing to do with vectors. And, c=a+b does refer to one integer. They are different...284 replies | 2806 view(s)
- 02-27-2017, 10:03 AMOkay, since we've confirmed that I get what you're saying, let's work backwards. Let's start with the binomial theorem. y=a^n+b^n+rmd(a,b,n) Now,...284 replies | 2806 view(s)
- 02-26-2017, 10:14 PMIcarus496 replied to a thread The energy that is lost in the interaction of matter and gravity with space in Questions and AnswersDo you mean gravitons? Because they have no rest mass. It's kind of like light. Higher wavelength light (think the colors of the rainbow) carries...12 replies | 242 view(s)
- 02-26-2017, 10:08 PMIcarus496 replied to a thread Does Electro-magnitism divided by Dark energy, equal Normal Matter ? in Questions and AnswersNo, that wouldn't make sense. For one, what do you mean "Electromagnetism divided by dark energy?" neither of those are numerical values, so you...1 replies | 1391 view(s)
- 02-26-2017, 09:51 PMI'm a high school student with an interest in physics and math. I learn fast (I like to think so, anyway) but I still don't have any formal education...1 replies | 82 view(s)
- 02-26-2017, 09:42 PMYeah, sorry, I said that wrong. I mean, the only solutions are where a or b are zero. My bad. I typed that wrong. Do I have it now, though?284 replies | 2806 view(s)
- 02-26-2017, 08:12 PMWith all due respect, I think you are overcomplicating the argument. Fermat's last theorem states: For a positive integer n>2, there are no non...284 replies | 2806 view(s)
- 02-26-2017, 05:08 PMRight, I understand the binomial expansion, but you can only apply the binomial theorem if you have something of the form (a+b)^n. If you set that...203 replies | 3163 view(s)
- 02-26-2017, 04:44 PMHey, buleria, Apologies in advance if I don't format this right, I have very little experience with latex I just wanted to point out that your...203 replies | 3163 view(s)

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