since light cannot escape the event horizon, does that mean the light is trapped yet still "shines" making the "inside" luminious?or is the gravity so strong that the photons cannot emit their energy?
since light cannot escape the event horizon, does that mean the light is trapped yet still "shines" making the "inside" luminious?or is the gravity so strong that the photons cannot emit their energy?
"the memories of a man in his old age are the deeds of a man in his prime"
ok people, is this just a stupid question or does anybody know?
"the memories of a man in his old age are the deeds of a man in his prime"
The radius of the event horizon is the Schwarzschild radius. An object's Schwarzschild radius is a tiny fraction of its radius prior to its gravitational collapse. For example, the Schwarzschild radius of Earth is 0.9 cm if Earth were to collapse into a black hole. You know that nothing can escape a black hole. However, nothing can enter the black hole. Prior to the collapse everywhere within the event horizon was incredibly hot dense solid. There could have never been a light there. Everything on the surface of the body prior to its collapse would have been crushed to an incredibly small size as is followed the surface. After the black hole is formed, nothing gets past the event horizon. The bottomline is that your question is moot. It is impossible to get a light inside a black hole.
What of light from an external source? Light from an external source gets red-shifted to DC as it approaches the event horizon. It can't enter the black hole.
But ofcourse there is a time when the black hole gets to "full" and blast of plasma jets out in two directions though you dont see the event horizon.
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